(2a^2b^2+4a^4b)+(3a^4b-2a^2b^2)=

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Solution for (2a^2b^2+4a^4b)+(3a^4b-2a^2b^2)= equation:


Simplifying
(2a2b2 + 4a4b) + (3a4b + -2a2b2) = 0

Remove parenthesis around (2a2b2 + 4a4b)
2a2b2 + 4a4b + (3a4b + -2a2b2) = 0

Reorder the terms:
2a2b2 + 4a4b + (-2a2b2 + 3a4b) = 0

Remove parenthesis around (-2a2b2 + 3a4b)
2a2b2 + 4a4b + -2a2b2 + 3a4b = 0

Reorder the terms:
2a2b2 + -2a2b2 + 4a4b + 3a4b = 0

Combine like terms: 2a2b2 + -2a2b2 = 0
0 + 4a4b + 3a4b = 0
4a4b + 3a4b = 0

Combine like terms: 4a4b + 3a4b = 7a4b
7a4b = 0

Solving
7a4b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '7'.
a4b = 0

Simplifying
a4b = 0

The solution to this equation could not be determined.

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